103102113131 has 2 divisors, whose sum is σ = 103102113132. Its totient is φ = 103102113130.

The previous prime is 103102113113. The next prime is 103102113193. The reversal of 103102113131 is 131311201301.

Together with previous prime (103102113113) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 103102113131 - 2¹⁸ = 103101850987 is a prime.

It is a super-2 number, since 2×103102113131² (a number of 23 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (103102113031) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51551056565 + 51551056566.

It is an arithmetic number, because the mean of its divisors is an integer number (51551056566).

Almost surely, 2^103102113131 is an apocalyptic number.

103102113131 is a deficient number, since it is larger than the sum of its proper divisors (1).

103102113131 is an equidigital number, since it uses as much as digits as its factorization.

103102113131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 103102113131 its reverse (131311201301), we get a palindrome (234413314432).

The spelling of 103102113131 in words is "one hundred three billion, one hundred two million, one hundred thirteen thousand, one hundred thirty-one".