Base | Representation |
---|---|
bin | 11110000000011011011… |
… | …00111000101000000001 |
3 | 10122120020200211101021021 |
4 | 33000031230320220001 |
5 | 113343013114133441 |
6 | 2105351152025441 |
7 | 134326454403211 |
oct | 17001554705001 |
9 | 3576220741237 |
10 | 1031022021121 |
11 | 368288063584 |
12 | 14799b232281 |
13 | 762c030b161 |
14 | 37c8a4d2241 |
15 | 1bc44e713d1 |
hex | f00db38a01 |
1031022021121 has 2 divisors, whose sum is σ = 1031022021122. Its totient is φ = 1031022021120.
The previous prime is 1031022021103. The next prime is 1031022021209. The reversal of 1031022021121 is 1211202201301.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 602697584896 + 428324436225 = 776336^2 + 654465^2 .
It is a cyclic number.
It is not a de Polignac number, because 1031022021121 - 217 = 1031021890049 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1031022021095 and 1031022021104.
It is not a weakly prime, because it can be changed into another prime (1031022021101) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 515511010560 + 515511010561.
It is an arithmetic number, because the mean of its divisors is an integer number (515511010561).
Almost surely, 21031022021121 is an apocalyptic number.
It is an amenable number.
1031022021121 is a deficient number, since it is larger than the sum of its proper divisors (1).
1031022021121 is an equidigital number, since it uses as much as digits as its factorization.
1031022021121 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 48, while the sum is 16.
Adding to 1031022021121 its reverse (1211202201301), we get a palindrome (2242224222422).
The spelling of 1031022021121 in words is "one trillion, thirty-one billion, twenty-two million, twenty-one thousand, one hundred twenty-one".
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