1031033000131 has 2 divisors, whose sum is σ = 1031033000132. Its totient is φ = 1031033000130.

The previous prime is 1031033000113. The next prime is 1031033000141. The reversal of 1031033000131 is 1310003301301.

Together with previous prime (1031033000113) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It is an emirp because it is prime and its reverse (1310003301301) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1031033000131 is a prime.

It is a super-2 number, since 2×1031033000131² (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1031033000141) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 515516500065 + 515516500066.

It is an arithmetic number, because the mean of its divisors is an integer number (515516500066).

Almost surely, 2^{1031033000131} is an apocalyptic number.

1031033000131 is a deficient number, since it is larger than the sum of its proper divisors (1).

1031033000131 is an equidigital number, since it uses as much as digits as its factorization.

1031033000131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 81, while the sum is 16.

Adding to 1031033000131 its reverse (1310003301301), we get a palindrome (2341036301432).

The spelling of 1031033000131 in words is "one trillion, thirty-one billion, thirty-three million, one hundred thirty-one", and thus it is an aban number.