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10311123040121 is a prime number
BaseRepresentation
bin1001011000001011111011…
…0100110111011101111001
31100111201210220010021010102
42112002332310313131321
52322414134444240441
633532510423325145
72112645145505231
oct226027664673571
940451726107112
1010311123040121
113315a17166a62
1211a64462b07b5
1359a447531377
142790bd60ccc1
1512d338d9769b
hex960bed37779

10311123040121 has 2 divisors, whose sum is σ = 10311123040122. Its totient is φ = 10311123040120.

The previous prime is 10311123040111. The next prime is 10311123040201. The reversal of 10311123040121 is 12104032111301.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 8072616325225 + 2238506714896 = 2841235^2 + 1496164^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-10311123040121 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 10311123040093 and 10311123040102.

It is not a weakly prime, because it can be changed into another prime (10311123040111) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5155561520060 + 5155561520061.

It is an arithmetic number, because the mean of its divisors is an integer number (5155561520061).

Almost surely, 210311123040121 is an apocalyptic number.

It is an amenable number.

10311123040121 is a deficient number, since it is larger than the sum of its proper divisors (1).

10311123040121 is an equidigital number, since it uses as much as digits as its factorization.

10311123040121 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 144, while the sum is 20.

Adding to 10311123040121 its reverse (12104032111301), we get a palindrome (22415155151422).

The spelling of 10311123040121 in words is "ten trillion, three hundred eleven billion, one hundred twenty-three million, forty thousand, one hundred twenty-one".