Base | Representation |
---|---|
bin | 10011001101001100… |
… | …00111000111000001 |
3 | 222121121100021221101 |
4 | 21212212013013001 |
5 | 132104131414332 |
6 | 4423100454401 |
7 | 513343523062 |
oct | 114646070701 |
9 | 28547307841 |
10 | 10311201217 |
11 | 441144a0a9 |
12 | 1bb924a401 |
13 | c8430a7c5 |
14 | 6db610569 |
15 | 405380ae7 |
hex | 2669871c1 |
10311201217 has 2 divisors, whose sum is σ = 10311201218. Its totient is φ = 10311201216.
The previous prime is 10311201191. The next prime is 10311201253. The reversal of 10311201217 is 71210211301.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 8444874816 + 1866326401 = 91896^2 + 43201^2 .
It is a cyclic number.
It is not a de Polignac number, because 10311201217 - 215 = 10311168449 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 10311201194 and 10311201203.
It is not a weakly prime, because it can be changed into another prime (10311201287) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5155600608 + 5155600609.
It is an arithmetic number, because the mean of its divisors is an integer number (5155600609).
Almost surely, 210311201217 is an apocalyptic number.
It is an amenable number.
10311201217 is a deficient number, since it is larger than the sum of its proper divisors (1).
10311201217 is an equidigital number, since it uses as much as digits as its factorization.
10311201217 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 84, while the sum is 19.
Adding to 10311201217 its reverse (71210211301), we get a palindrome (81521412518).
The spelling of 10311201217 in words is "ten billion, three hundred eleven million, two hundred one thousand, two hundred seventeen".
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