Base | Representation |
---|---|
bin | 1001011000001100010000… |
… | …0000101101100000110001 |
3 | 1100111202000221210212101111 |
4 | 2112003010000231200301 |
5 | 2322414324231444103 |
6 | 33532523212033321 |
7 | 2112650253066343 |
oct | 226030400554061 |
9 | 40452027725344 |
10 | 10311210031153 |
11 | 3315a61282679 |
12 | 11a646b462841 |
13 | 59a45c56b855 |
14 | 2790cadb5293 |
15 | 12d34182c86d |
hex | 960c402d831 |
10311210031153 has 2 divisors, whose sum is σ = 10311210031154. Its totient is φ = 10311210031152.
The previous prime is 10311210031097. The next prime is 10311210031169. The reversal of 10311210031153 is 35113001211301.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 5494115666209 + 4817094364944 = 2343953^2 + 2194788^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-10311210031153 is a prime.
It is not a weakly prime, because it can be changed into another prime (10311210031453) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5155605015576 + 5155605015577.
It is an arithmetic number, because the mean of its divisors is an integer number (5155605015577).
Almost surely, 210311210031153 is an apocalyptic number.
It is an amenable number.
10311210031153 is a deficient number, since it is larger than the sum of its proper divisors (1).
10311210031153 is an equidigital number, since it uses as much as digits as its factorization.
10311210031153 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 270, while the sum is 22.
Adding to 10311210031153 its reverse (35113001211301), we get a palindrome (45424211242454).
The spelling of 10311210031153 in words is "ten trillion, three hundred eleven billion, two hundred ten million, thirty-one thousand, one hundred fifty-three".
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