103112113130330 has 16 divisors (see below), whose sum is σ = 189918124650144. Its totient is φ = 40285662804240.

The previous prime is 103112113130329. The next prime is 103112113130353. The reversal of 103112113130330 is 33031311211301.

It is a junction number, because it is equal to n+sod(n) for n = 103112113130296 and 103112113130305.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 119897805536 + ... + 119897806395.

It is an arithmetic number, because the mean of its divisors is an integer number (11869882790634).

Almost surely, 2^{103112113130330} is an apocalyptic number.

103112113130330 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

103112113130330 is a deficient number, since it is larger than the sum of its proper divisors (86806011519814).

103112113130330 is a wasteful number, since it uses less digits than its factorization.

103112113130330 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 239795611981.

The product of its (nonzero) digits is 486, while the sum is 23.

Adding to 103112113130330 its reverse (33031311211301), we get a palindrome (136143424341631).

The spelling of 103112113130330 in words is "one hundred three trillion, one hundred twelve billion, one hundred thirteen million, one hundred thirty thousand, three hundred thirty".