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1031130311210 = 25103113031121
BaseRepresentation
bin11110000000101000010…
…01111110101000101010
310122120112020121002100022
433000110021332220222
5113343223324424320
62105410021040442
7134332241013566
oct17002411765052
93576466532308
101031130311210
113683331a751a
12147a0b556122
137630989512c
1437c9aa406a6
151bc4e712325
hexf01427ea2a

1031130311210 has 8 divisors (see below), whose sum is σ = 1856034560196. Its totient is φ = 412452124480.

The previous prime is 1031130311171. The next prime is 1031130311251. The reversal of 1031130311210 is 121130311301.

It can be written as a sum of positive squares in 2 ways, for example, as 990058830289 + 41071480921 = 995017^2 + 202661^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 51556515551 + ... + 51556515570.

Almost surely, 21031130311210 is an apocalyptic number.

1031130311210 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

1031130311210 is a deficient number, since it is larger than the sum of its proper divisors (824904248986).

1031130311210 is a wasteful number, since it uses less digits than its factorization.

1031130311210 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 103113031128.

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 1031130311210 its reverse (121130311301), we get a palindrome (1152260622511).

Subtracting from 1031130311210 its reverse (121130311301), we obtain a palindrome (909999999909).

The spelling of 1031130311210 in words is "one trillion, thirty-one billion, one hundred thirty million, three hundred eleven thousand, two hundred ten".

Divisors: 1 2 5 10 103113031121 206226062242 515565155605 1031130311210