Base | Representation |
---|---|
bin | 1001011000001100100110… |
… | …0011110101010111001001 |
3 | 1100111202021102222111100110 |
4 | 2112003021203311113021 |
5 | 2322420022044440200 |
6 | 33532540335224533 |
7 | 2112652463264322 |
oct | 226031143652711 |
9 | 40452242874313 |
10 | 10311303124425 |
11 | 3315aa9886a66 |
12 | 11a6496678149 |
13 | 59a475934724 |
14 | 2790d94c9449 |
15 | 12d349abab50 |
hex | 960c98f55c9 |
10311303124425 has 12 divisors (see below), whose sum is σ = 17048021165840. Its totient is φ = 5499361666320.
The previous prime is 10311303124403. The next prime is 10311303124471. The reversal of 10311303124425 is 52442130311301.
It is not a de Polignac number, because 10311303124425 - 220 = 10311302075849 is a prime.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 10311303124392 and 10311303124401.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 68742020755 + ... + 68742020904.
Almost surely, 210311303124425 is an apocalyptic number.
10311303124425 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
10311303124425 is a deficient number, since it is larger than the sum of its proper divisors (6736718041415).
10311303124425 is a wasteful number, since it uses less digits than its factorization.
10311303124425 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 137484041672 (or 137484041667 counting only the distinct ones).
The product of its (nonzero) digits is 8640, while the sum is 30.
Adding to 10311303124425 its reverse (52442130311301), we get a palindrome (62753433435726).
The spelling of 10311303124425 in words is "ten trillion, three hundred eleven billion, three hundred three million, one hundred twenty-four thousand, four hundred twenty-five".
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