Base | Representation |
---|---|
bin | 11110000000101000010… |
… | …01111111000101001001 |
3 | 10122120112020121011211211 |
4 | 33000110021333011021 |
5 | 113343223330004113 |
6 | 2105410021053121 |
7 | 134332241022112 |
oct | 17002411770511 |
9 | 3576466534754 |
10 | 1031130313033 |
11 | 3683331a8927 |
12 | 147a0b5571a1 |
13 | 76309895c02 |
14 | 37c9aa41209 |
15 | 1bc4e712b3d |
hex | f01427f149 |
1031130313033 has 2 divisors, whose sum is σ = 1031130313034. Its totient is φ = 1031130313032.
The previous prime is 1031130313019. The next prime is 1031130313069. The reversal of 1031130313033 is 3303130311301.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 811518110649 + 219612202384 = 900843^2 + 468628^2 .
It is a cyclic number.
It is not a de Polignac number, because 1031130313033 - 25 = 1031130313001 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1031130312995 and 1031130313013.
It is not a weakly prime, because it can be changed into another prime (1031130313133) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 515565156516 + 515565156517.
It is an arithmetic number, because the mean of its divisors is an integer number (515565156517).
Almost surely, 21031130313033 is an apocalyptic number.
It is an amenable number.
1031130313033 is a deficient number, since it is larger than the sum of its proper divisors (1).
1031130313033 is an equidigital number, since it uses as much as digits as its factorization.
1031130313033 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 729, while the sum is 22.
Adding to 1031130313033 its reverse (3303130311301), we get a palindrome (4334260624334).
The spelling of 1031130313033 in words is "one trillion, thirty-one billion, one hundred thirty million, three hundred thirteen thousand, thirty-three".
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