10311320013 has 8 divisors (see below), whose sum is σ = 13973810976. Its totient is φ = 6761521200.

The previous prime is 10311319999. The next prime is 10311320021. The reversal of 10311320013 is 31002311301.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 10311320013 - 2⁵ = 10311319981 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 10311319974 and 10311320001.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (10311320113) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 28172823 + ... + 28173188.

It is an arithmetic number, because the mean of its divisors is an integer number (1746726372).

Almost surely, 2^10311320013 is an apocalyptic number.

It is an amenable number.

10311320013 is a deficient number, since it is larger than the sum of its proper divisors (3662490963).

10311320013 is an equidigital number, since it uses as much as digits as its factorization.

10311320013 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 56346075.

The product of its (nonzero) digits is 54, while the sum is 15.

Adding to 10311320013 its reverse (31002311301), we get a palindrome (41313631314).

The spelling of 10311320013 in words is "ten billion, three hundred eleven million, three hundred twenty thousand, thirteen".