10311319981 has 2 divisors, whose sum is σ = 10311319982. Its totient is φ = 10311319980.

The previous prime is 10311319979. The next prime is 10311319999. The reversal of 10311319981 is 18991311301.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 6861637225 + 3449682756 = 82835^2 + 58734^2 .

It is a cyclic number.

It is not a de Polignac number, because 10311319981 - 2¹ = 10311319979 is a prime.

It is a super-2 number, since 2×10311319981² (a number of 21 digits) contains 22 as substring.

Together with 10311319979, it forms a pair of twin primes.

It is a self number, because there is not a number n which added to its sum of digits gives 10311319981.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10311319181) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5155659990 + 5155659991.

It is an arithmetic number, because the mean of its divisors is an integer number (5155659991).

Almost surely, 2^10311319981 is an apocalyptic number.

It is an amenable number.

10311319981 is a deficient number, since it is larger than the sum of its proper divisors (1).

10311319981 is an equidigital number, since it uses as much as digits as its factorization.

10311319981 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5832, while the sum is 37.

The spelling of 10311319981 in words is "ten billion, three hundred eleven million, three hundred nineteen thousand, nine hundred eighty-one".