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10311320300041 is a prime number
BaseRepresentation
bin1001011000001100101010…
…0101010110101000001001
31100111202022122022002212101
42112003022211112220021
52322420040444100131
633532542151313401
72112653062261105
oct226031245265011
940452278262771
1010311320300041
113316008548292
1211a64a037b861
1359a479369407
142790db8ba905
1512d34b35ec61
hex960ca956a09

10311320300041 has 2 divisors, whose sum is σ = 10311320300042. Its totient is φ = 10311320300040.

The previous prime is 10311320300033. The next prime is 10311320300069. The reversal of 10311320300041 is 14000302311301.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 10048925360016 + 262394940025 = 3170004^2 + 512245^2 .

It is an emirp because it is prime and its reverse (14000302311301) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 10311320300041 - 23 = 10311320300033 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 10311320299991 and 10311320300018.

It is not a weakly prime, because it can be changed into another prime (10311320300011) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5155660150020 + 5155660150021.

It is an arithmetic number, because the mean of its divisors is an integer number (5155660150021).

Almost surely, 210311320300041 is an apocalyptic number.

It is an amenable number.

10311320300041 is a deficient number, since it is larger than the sum of its proper divisors (1).

10311320300041 is an equidigital number, since it uses as much as digits as its factorization.

10311320300041 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 216, while the sum is 19.

Adding to 10311320300041 its reverse (14000302311301), we get a palindrome (24311622611342).

The spelling of 10311320300041 in words is "ten trillion, three hundred eleven billion, three hundred twenty million, three hundred thousand, forty-one".