Base | Representation |
---|---|
bin | 10111011100100110010001… |
… | …000001111011010111100100 |
3 | 111112010012112012220222121000 |
4 | 113130212101001323113210 |
5 | 102004010340032330200 |
6 | 1003152451353153300 |
7 | 30502124145132531 |
oct | 2734462101732744 |
9 | 445105465828530 |
10 | 103120303011300 |
11 | 2a948090788933 |
12 | b6954a49bb830 |
13 | 4570283873823 |
14 | 1b670993a9d88 |
15 | bdc5e08c0300 |
hex | 5dc99107b5e4 |
103120303011300 has 288 divisors, whose sum is σ = 333048296044800. Its totient is φ = 27371578752000.
The previous prime is 103120303011269. The next prime is 103120303011343. The reversal of 103120303011300 is 3110303021301.
It is a happy number.
103120303011300 is a `hidden beast` number, since 1 + 0 + 31 + 2 + 0 + 30 + 301 + 1 + 300 = 666.
It is a Harshad number since it is a multiple of its sum of digits (18).
It is an unprimeable number.
It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 713864481 + ... + 714008919.
It is an arithmetic number, because the mean of its divisors is an integer number (1156417694600).
Almost surely, 2103120303011300 is an apocalyptic number.
103120303011300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 103120303011300, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (166524148022400).
103120303011300 is an abundant number, since it is smaller than the sum of its proper divisors (229927993033500).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
103120303011300 is a wasteful number, since it uses less digits than its factorization.
103120303011300 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 145684 (or 145671 counting only the distinct ones).
The product of its (nonzero) digits is 162, while the sum is 18.
Adding to 103120303011300 its reverse (3110303021301), we get a palindrome (106230606032601).
The spelling of 103120303011300 in words is "one hundred three trillion, one hundred twenty billion, three hundred three million, eleven thousand, three hundred".
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