10312110001 has 4 divisors (see below), whose sum is σ = 10317397504. Its totient is φ = 10306822500.

The previous prime is 10312109993. The next prime is 10312110023. The reversal of 10312110001 is 10001121301.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 10312110001 - 2³ = 10312109993 is a prime.

It is a super-2 number, since 2×10312110001² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 10312110001.

It is not an unprimeable number, because it can be changed into a prime (10312110031) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2640825 + ... + 2644726.

It is an arithmetic number, because the mean of its divisors is an integer number (2579349376).

Almost surely, 2^10312110001 is an apocalyptic number.

It is an amenable number.

10312110001 is a deficient number, since it is larger than the sum of its proper divisors (5287503).

10312110001 is an equidigital number, since it uses as much as digits as its factorization.

10312110001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5287502.

The product of its (nonzero) digits is 6, while the sum is 10.

Adding to 10312110001 its reverse (10001121301), we get a palindrome (20313231302).

The spelling of 10312110001 in words is "ten billion, three hundred twelve million, one hundred ten thousand, one".