Base | Representation |
---|---|
bin | 10011001101010011… |
… | …00100111110101001 |
3 | 222121200001110112202 |
4 | 21212221210332221 |
5 | 132104400004433 |
6 | 4423132145545 |
7 | 513354326423 |
oct | 114651447651 |
9 | 28550043482 |
10 | 10312109993 |
11 | 4411a0a959 |
12 | 1bb96082b5 |
13 | c84568343 |
14 | 6db7a9813 |
15 | 4054aeee8 |
hex | 266a64fa9 |
10312109993 has 2 divisors, whose sum is σ = 10312109994. Its totient is φ = 10312109992.
The previous prime is 10312109981. The next prime is 10312110023. The reversal of 10312109993 is 39990121301.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 5388000409 + 4924109584 = 73403^2 + 70172^2 .
It is a cyclic number.
It is not a de Polignac number, because 10312109993 - 212 = 10312105897 is a prime.
It is a super-2 number, since 2×103121099932 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (10312109903) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5156054996 + 5156054997.
It is an arithmetic number, because the mean of its divisors is an integer number (5156054997).
Almost surely, 210312109993 is an apocalyptic number.
It is an amenable number.
10312109993 is a deficient number, since it is larger than the sum of its proper divisors (1).
10312109993 is an equidigital number, since it uses as much as digits as its factorization.
10312109993 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 13122, while the sum is 38.
The spelling of 10312109993 in words is "ten billion, three hundred twelve million, one hundred nine thousand, nine hundred ninety-three".
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