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103121233112993 is a prime number
BaseRepresentation
bin10111011100100111001000…
…011101111110111110100001
3111112010021221001002001020212
4113130213020131332332201
5102004014241134103433
61003153123540343505
730502156200642344
oct2734471035767641
9445107831061225
10103121233112993
112a948518800017
12b6957043a4b95
1345703a1479564
141b67146b2045b
15bdc647395d48
hex5dc9c877efa1

103121233112993 has 2 divisors, whose sum is σ = 103121233112994. Its totient is φ = 103121233112992.

The previous prime is 103121233112921. The next prime is 103121233113023. The reversal of 103121233112993 is 399211332121301.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 55121596569664 + 47999636543329 = 7424392^2 + 6928177^2 .

It is a cyclic number.

It is not a de Polignac number, because 103121233112993 - 218 = 103121232850849 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 103121233112993.

It is not a weakly prime, because it can be changed into another prime (103121233112903) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51560616556496 + 51560616556497.

It is an arithmetic number, because the mean of its divisors is an integer number (51560616556497).

Almost surely, 2103121233112993 is an apocalyptic number.

It is an amenable number.

103121233112993 is a deficient number, since it is larger than the sum of its proper divisors (1).

103121233112993 is an equidigital number, since it uses as much as digits as its factorization.

103121233112993 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 52488, while the sum is 41.

The spelling of 103121233112993 in words is "one hundred three trillion, one hundred twenty-one billion, two hundred thirty-three million, one hundred twelve thousand, nine hundred ninety-three".