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1031213212222 = 2515606606111
BaseRepresentation
bin11110000000110010001…
…10001110001000111110
310122120202000120220011011
433000121012032020332
5113343411040242342
62105422141545434
7134334265451524
oct17003106161076
93576660526134
101031213212222
11368375a7a256
12147a3327527a
1376320acca9b
1437ca7a60314
151bc56b3a717
hexf01918e23e

1031213212222 has 4 divisors (see below), whose sum is σ = 1546819818336. Its totient is φ = 515606606110.

The previous prime is 1031213212193. The next prime is 1031213212319. The reversal of 1031213212222 is 2222123121301.

It is a semiprime because it is the product of two primes.

It is a super-2 number, since 2×10312132122222 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1031213212193 and 1031213212202.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 257803303054 + ... + 257803303057.

It is an arithmetic number, because the mean of its divisors is an integer number (386704954584).

Almost surely, 21031213212222 is an apocalyptic number.

1031213212222 is a deficient number, since it is larger than the sum of its proper divisors (515606606114).

1031213212222 is an equidigital number, since it uses as much as digits as its factorization.

1031213212222 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 515606606113.

The product of its (nonzero) digits is 576, while the sum is 22.

Adding to 1031213212222 its reverse (2222123121301), we get a palindrome (3253336333523).

The spelling of 1031213212222 in words is "one trillion, thirty-one billion, two hundred thirteen million, two hundred twelve thousand, two hundred twenty-two".

Divisors: 1 2 515606606111 1031213212222