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103121974537 is a prime number
BaseRepresentation
bin110000000001010001…
…1000111010100001001
3100212011202012002012021
41200002203013110021
53142143211141122
6115212405444441
710310313215041
oct1400243072411
9325152162167
10103121974537
113a80873684a
1217b9b410721
13995555c85a
144dc3938721
152a383741c7
hex18028c7509

103121974537 has 2 divisors, whose sum is σ = 103121974538. Its totient is φ = 103121974536.

The previous prime is 103121974531. The next prime is 103121974573. The reversal of 103121974537 is 735479121301.

Together with next prime (103121974573) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 94030542736 + 9091431801 = 306644^2 + 95349^2 .

It is a cyclic number.

It is not a de Polignac number, because 103121974537 - 211 = 103121972489 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 103121974493 and 103121974502.

It is not a weakly prime, because it can be changed into another prime (103121974531) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51560987268 + 51560987269.

It is an arithmetic number, because the mean of its divisors is an integer number (51560987269).

Almost surely, 2103121974537 is an apocalyptic number.

It is an amenable number.

103121974537 is a deficient number, since it is larger than the sum of its proper divisors (1).

103121974537 is an equidigital number, since it uses as much as digits as its factorization.

103121974537 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 158760, while the sum is 43.

The spelling of 103121974537 in words is "one hundred three billion, one hundred twenty-one million, nine hundred seventy-four thousand, five hundred thirty-seven".