Base | Representation |
---|---|
bin | 110000000001010001… |
… | …1010010011100110011 |
3 | 100212011202021101202112 |
4 | 1200002203102130303 |
5 | 3142143214121042 |
6 | 115212410435535 |
7 | 10310313465026 |
oct | 1400243223463 |
9 | 325152241675 |
10 | 103122020147 |
11 | 3a808768043 |
12 | 17b9b432bab |
13 | 9955577543 |
14 | 4dc394b1bd |
15 | 2a38382982 |
hex | 18028d2733 |
103122020147 has 2 divisors, whose sum is σ = 103122020148. Its totient is φ = 103122020146.
The previous prime is 103122020033. The next prime is 103122020161. The reversal of 103122020147 is 741020221301.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 103122020147 - 210 = 103122019123 is a prime.
It is not a weakly prime, because it can be changed into another prime (103122020647) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51561010073 + 51561010074.
It is an arithmetic number, because the mean of its divisors is an integer number (51561010074).
Almost surely, 2103122020147 is an apocalyptic number.
103122020147 is a deficient number, since it is larger than the sum of its proper divisors (1).
103122020147 is an equidigital number, since it uses as much as digits as its factorization.
103122020147 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 672, while the sum is 23.
Adding to 103122020147 its reverse (741020221301), we get a palindrome (844142241448).
The spelling of 103122020147 in words is "one hundred three billion, one hundred twenty-two million, twenty thousand, one hundred forty-seven".
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