Base | Representation |
---|---|
bin | 11110000000110011000… |
… | …01010110001111011011 |
3 | 10122120202111222011201002 |
4 | 33000121201112033123 |
5 | 113343414400321131 |
6 | 2105422554215215 |
7 | 134334413056514 |
oct | 17003141261733 |
9 | 3576674864632 |
10 | 1031220323291 |
11 | 368379a96974 |
12 | 147a3572450b |
13 | 7632241c712 |
14 | 37ca8991a0b |
15 | 1bc575926cb |
hex | f0198563db |
1031220323291 has 2 divisors, whose sum is σ = 1031220323292. Its totient is φ = 1031220323290.
The previous prime is 1031220323279. The next prime is 1031220323417. The reversal of 1031220323291 is 1923230221301.
1031220323291 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is an emirp because it is prime and its reverse (1923230221301) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1031220323291 - 230 = 1030146581467 is a prime.
It is not a weakly prime, because it can be changed into another prime (1031220323251) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 515610161645 + 515610161646.
It is an arithmetic number, because the mean of its divisors is an integer number (515610161646).
Almost surely, 21031220323291 is an apocalyptic number.
1031220323291 is a deficient number, since it is larger than the sum of its proper divisors (1).
1031220323291 is an equidigital number, since it uses as much as digits as its factorization.
1031220323291 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3888, while the sum is 29.
Adding to 1031220323291 its reverse (1923230221301), we get a palindrome (2954450544592).
The spelling of 1031220323291 in words is "one trillion, thirty-one billion, two hundred twenty million, three hundred twenty-three thousand, two hundred ninety-one".
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