Base | Representation |
---|---|
bin | 110000000001010001… |
… | …1100110111011110011 |
3 | 100212011202102122212002 |
4 | 1200002203212323303 |
5 | 3142143224312201 |
6 | 115212412324215 |
7 | 10310314264451 |
oct | 1400243467363 |
9 | 325152378762 |
10 | 103122104051 |
11 | 3a80881508a |
12 | 17b9b47366b |
13 | 99555a67a5 |
14 | 4dc396d9d1 |
15 | 2a3839c76b |
hex | 18028e6ef3 |
103122104051 has 2 divisors, whose sum is σ = 103122104052. Its totient is φ = 103122104050.
The previous prime is 103122104039. The next prime is 103122104077. The reversal of 103122104051 is 150401221301.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 103122104051 - 210 = 103122103027 is a prime.
It is a super-2 number, since 2×1031221040512 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (103122104251) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51561052025 + 51561052026.
It is an arithmetic number, because the mean of its divisors is an integer number (51561052026).
Almost surely, 2103122104051 is an apocalyptic number.
103122104051 is a deficient number, since it is larger than the sum of its proper divisors (1).
103122104051 is an equidigital number, since it uses as much as digits as its factorization.
103122104051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 240, while the sum is 20.
Adding to 103122104051 its reverse (150401221301), we get a palindrome (253523325352).
The spelling of 103122104051 in words is "one hundred three billion, one hundred twenty-two million, one hundred four thousand, fifty-one".
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