Base | Representation |
---|---|
bin | 11110000000110101100… |
… | …01110111100011010001 |
3 | 10122120210222200120101022 |
4 | 33000122301313203101 |
5 | 113343440301244444 |
6 | 2105425030445225 |
7 | 134335060351661 |
oct | 17003261674321 |
9 | 3576728616338 |
10 | 1031241431249 |
11 | 36838a9a3667 |
12 | 147a40803815 |
13 | 76326900233 |
14 | 37cab6c81a1 |
15 | 1bc593619ee |
hex | f01ac778d1 |
1031241431249 has 2 divisors, whose sum is σ = 1031241431250. Its totient is φ = 1031241431248.
The previous prime is 1031241431201. The next prime is 1031241431267. The reversal of 1031241431249 is 9421341421301.
1031241431249 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1015142896849 + 16098534400 = 1007543^2 + 126880^2 .
It is a cyclic number.
It is not a de Polignac number, because 1031241431249 - 232 = 1026946463953 is a prime.
It is not a weakly prime, because it can be changed into another prime (1031241431279) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 515620715624 + 515620715625.
It is an arithmetic number, because the mean of its divisors is an integer number (515620715625).
Almost surely, 21031241431249 is an apocalyptic number.
It is an amenable number.
1031241431249 is a deficient number, since it is larger than the sum of its proper divisors (1).
1031241431249 is an equidigital number, since it uses as much as digits as its factorization.
1031241431249 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 20736, while the sum is 35.
The spelling of 1031241431249 in words is "one trillion, thirty-one billion, two hundred forty-one million, four hundred thirty-one thousand, two hundred forty-nine".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.074 sec. • engine limits •