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103125442014005 = 5591204929013011
BaseRepresentation
bin10111011100101011000011…
…010101101010101100110101
3111112010200210100212101000112
4113130223003111222230311
5102004101401123422010
61003155101331552405
730502365406004645
oct2734530325525465
9445120710771015
10103125442014005
112a94a2885a6704
12b696499a5b705
1345708c2450828
141b67425ad2525
15bdc7e1b32a05
hex5dcac356ab35

103125442014005 has 16 divisors (see below), whose sum is σ = 125858446056000. Its totient is φ = 81095308719360.

The previous prime is 103125442013983. The next prime is 103125442014031. The reversal of 103125442014005 is 500410244521301.

It is not a de Polignac number, because 103125442014005 - 220 = 103125440965429 is a prime.

It is a super-2 number, since 2×1031254420140052 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 10952051 + ... + 18060960.

It is an arithmetic number, because the mean of its divisors is an integer number (7866152878500).

Almost surely, 2103125442014005 is an apocalyptic number.

It is an amenable number.

103125442014005 is a deficient number, since it is larger than the sum of its proper divisors (22733004041995).

103125442014005 is a wasteful number, since it uses less digits than its factorization.

103125442014005 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 29025124.

The product of its (nonzero) digits is 19200, while the sum is 32.

Adding to 103125442014005 its reverse (500410244521301), we get a palindrome (603535686535306).

The spelling of 103125442014005 in words is "one hundred three trillion, one hundred twenty-five billion, four hundred forty-two million, fourteen thousand, five".

Divisors: 1 5 59 295 12049 60245 710891 3554455 29013011 145065055 1711767649 8558838245 349577769539 1747888847695 20625088402801 103125442014005