Base | Representation |
---|---|
bin | 1001011000010001011110… |
… | …1101110010000001101011 |
3 | 1100111212122211021220121201 |
4 | 2112010113231302001223 |
5 | 2322430213233330201 |
6 | 33533314415345031 |
7 | 2113030124461201 |
oct | 226042755620153 |
9 | 40455584256551 |
10 | 10312614355051 |
11 | 3316611a54a38 |
12 | 11a67a1822177 |
13 | 59a6244a2438 |
14 | 2791c16d1071 |
15 | 12d3c4c78801 |
hex | 96117b7206b |
10312614355051 has 2 divisors, whose sum is σ = 10312614355052. Its totient is φ = 10312614355050.
The previous prime is 10312614355007. The next prime is 10312614355063. The reversal of 10312614355051 is 15055341621301.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-10312614355051 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 10312614355051.
It is not a weakly prime, because it can be changed into another prime (10312614355081) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5156307177525 + 5156307177526.
It is an arithmetic number, because the mean of its divisors is an integer number (5156307177526).
Almost surely, 210312614355051 is an apocalyptic number.
10312614355051 is a deficient number, since it is larger than the sum of its proper divisors (1).
10312614355051 is an equidigital number, since it uses as much as digits as its factorization.
10312614355051 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 54000, while the sum is 37.
Adding to 10312614355051 its reverse (15055341621301), we get a palindrome (25367955976352).
The spelling of 10312614355051 in words is "ten trillion, three hundred twelve billion, six hundred fourteen million, three hundred fifty-five thousand, fifty-one".
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