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103130010333113 is a prime number
BaseRepresentation
bin10111011100101111010011…
…101000011010111110111001
3111112011010120201222000201112
4113130233103220122332321
5102004140230121124423
61003201134522530105
730502616540041361
oct2734572350327671
9445133521860645
10103130010333113
112a95121226a445
12b697353966935
13457116ca27a2a
141b6773a7039a1
15bdc9acc18a78
hex5dcbd3a1afb9

103130010333113 has 2 divisors, whose sum is σ = 103130010333114. Its totient is φ = 103130010333112.

The previous prime is 103130010333109. The next prime is 103130010333149. The reversal of 103130010333113 is 311333010031301.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 102271697024809 + 858313308304 = 10112947^2 + 926452^2 .

It is a cyclic number.

It is not a de Polignac number, because 103130010333113 - 22 = 103130010333109 is a prime.

It is not a weakly prime, because it can be changed into another prime (103130010332113) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51565005166556 + 51565005166557.

It is an arithmetic number, because the mean of its divisors is an integer number (51565005166557).

Almost surely, 2103130010333113 is an apocalyptic number.

It is an amenable number.

103130010333113 is a deficient number, since it is larger than the sum of its proper divisors (1).

103130010333113 is an equidigital number, since it uses as much as digits as its factorization.

103130010333113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 729, while the sum is 23.

Adding to 103130010333113 its reverse (311333010031301), we get a palindrome (414463020364414).

The spelling of 103130010333113 in words is "one hundred three trillion, one hundred thirty billion, ten million, three hundred thirty-three thousand, one hundred thirteen".