Search a number
-
+
1031301313102 = 2515650656551
BaseRepresentation
bin11110000000111100101…
…10010011001001001110
310122120222011100212211201
433000132112103021032
5113344101114004402
62105435010140114
7134336415344434
oct17003626231116
93576864325751
101031301313102
113684107837a5
12147a5888163a
1376336138498
1437cb5634d54
151bc5e73e687
hexf01e59324e

1031301313102 has 4 divisors (see below), whose sum is σ = 1546951969656. Its totient is φ = 515650656550.

The previous prime is 1031301313087. The next prime is 1031301313117. The reversal of 1031301313102 is 2013131031301.

It is a semiprime because it is the product of two primes.

It is an interprime number because it is at equal distance from previous prime (1031301313087) and next prime (1031301313117).

It is a self number, because there is not a number n which added to its sum of digits gives 1031301313102.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 257825328274 + ... + 257825328277.

It is an arithmetic number, because the mean of its divisors is an integer number (386737992414).

Almost surely, 21031301313102 is an apocalyptic number.

1031301313102 is a deficient number, since it is larger than the sum of its proper divisors (515650656554).

1031301313102 is an equidigital number, since it uses as much as digits as its factorization.

1031301313102 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 515650656553.

The product of its (nonzero) digits is 162, while the sum is 19.

Adding to 1031301313102 its reverse (2013131031301), we get a palindrome (3044432344403).

The spelling of 1031301313102 in words is "one trillion, thirty-one billion, three hundred one million, three hundred thirteen thousand, one hundred two".

Divisors: 1 2 515650656551 1031301313102