Base | Representation |
---|---|
bin | 111101011110000… |
… | …111011100101001 |
3 | 2122212120201111112 |
4 | 331132013130221 |
5 | 4103003230001 |
6 | 250200240105 |
7 | 34361643056 |
oct | 7536073451 |
9 | 2585521445 |
10 | 1031305001 |
11 | 48a165791 |
12 | 249470035 |
13 | 13587b15c |
14 | 9ad7a02d |
15 | 60816cbb |
hex | 3d787729 |
1031305001 has 2 divisors, whose sum is σ = 1031305002. Its totient is φ = 1031305000.
The previous prime is 1031304997. The next prime is 1031305031. The reversal of 1031305001 is 1005031301.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 979752601 + 51552400 = 31301^2 + 7180^2 .
It is a cyclic number.
It is not a de Polignac number, because 1031305001 - 22 = 1031304997 is a prime.
It is a super-2 number, since 2×10313050012 = 2127180010175220002, which contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1031305031) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 515652500 + 515652501.
It is an arithmetic number, because the mean of its divisors is an integer number (515652501).
Almost surely, 21031305001 is an apocalyptic number.
It is an amenable number.
1031305001 is a deficient number, since it is larger than the sum of its proper divisors (1).
1031305001 is an equidigital number, since it uses as much as digits as its factorization.
1031305001 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 45, while the sum is 14.
The square root of 1031305001 is about 32113.9377996533. The cubic root of 1031305001 is about 1010.3279662296.
Adding to 1031305001 its reverse (1005031301), we get a palindrome (2036336302).
The spelling of 1031305001 in words is "one billion, thirty-one million, three hundred five thousand, one".
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