Base | Representation |
---|---|
bin | 11110000000111101110… |
… | …11010010110111111011 |
3 | 10122120222211121121022002 |
4 | 33000132323102313323 |
5 | 113344111104330243 |
6 | 2105435554051215 |
7 | 134336563646225 |
oct | 17003673226773 |
9 | 3576884547262 |
10 | 1031311011323 |
11 | 3684161a815a |
12 | 147a5bb79b0b |
13 | 76338152888 |
14 | 37cb6a3b415 |
15 | 1bc60507eb8 |
hex | f01eed2dfb |
1031311011323 has 2 divisors, whose sum is σ = 1031311011324. Its totient is φ = 1031311011322.
The previous prime is 1031311011317. The next prime is 1031311011391. The reversal of 1031311011323 is 3231101131301.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1031311011323 - 222 = 1031306817019 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1031311011295 and 1031311011304.
It is not a weakly prime, because it can be changed into another prime (1031311011023) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 515655505661 + 515655505662.
It is an arithmetic number, because the mean of its divisors is an integer number (515655505662).
Almost surely, 21031311011323 is an apocalyptic number.
1031311011323 is a deficient number, since it is larger than the sum of its proper divisors (1).
1031311011323 is an equidigital number, since it uses as much as digits as its factorization.
1031311011323 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 162, while the sum is 20.
Adding to 1031311011323 its reverse (3231101131301), we get a palindrome (4262412142624).
The spelling of 1031311011323 in words is "one trillion, thirty-one billion, three hundred eleven million, eleven thousand, three hundred twenty-three".
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