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103131113104132 = 2267338310220321
BaseRepresentation
bin10111011100110000010101…
…010111001010001100000100
3111112011020102121000121011121
4113130300111113022030010
5102004200004423313012
61003201440155043324
730502656060325261
oct2734602527121404
9445136377017147
10103131113104132
112a9517287a7653
12b697601140544
1345712b7338a69
141b67802d64268
15bdca2494aa07
hex5dcc155ca304

103131113104132 has 12 divisors (see below), whose sum is σ = 180747619479196. Its totient is φ = 51488936110080.

The previous prime is 103131113104121. The next prime is 103131113104207. The reversal of 103131113104132 is 231401311131301.

It can be written as a sum of positive squares in 2 ways, for example, as 59185695514176 + 43945417589956 = 7693224^2 + 6629134^2 .

It is a junction number, because it is equal to n+sod(n) for n = 103131113104097 and 103131113104106.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 19155107469 + ... + 19155112852.

Almost surely, 2103131113104132 is an apocalyptic number.

It is an amenable number.

103131113104132 is a deficient number, since it is larger than the sum of its proper divisors (77616506375064).

103131113104132 is a wasteful number, since it uses less digits than its factorization.

103131113104132 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 38310220998 (or 38310220996 counting only the distinct ones).

The product of its (nonzero) digits is 648, while the sum is 25.

Adding to 103131113104132 its reverse (231401311131301), we get a palindrome (334532424235433).

The spelling of 103131113104132 in words is "one hundred three trillion, one hundred thirty-one billion, one hundred thirteen million, one hundred four thousand, one hundred thirty-two".

Divisors: 1 2 4 673 1346 2692 38310220321 76620440642 153240881284 25782778276033 51565556552066 103131113104132