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103131120214 = 2303716979111
BaseRepresentation
bin110000000001100011…
…0000000001001010110
3100212012101101201201001
41200003012000021112
53142203031321324
6115213333453514
710310454025603
oct1400306001126
9325171351631
10103131120214
113a812913061
1217ba24a129a
1399574125b5
144dc4c396aa
152a3907de44
hex1803180256

103131120214 has 8 divisors (see below), whose sum is σ = 154747626768. Its totient is φ = 51548577960.

The previous prime is 103131120187. The next prime is 103131120289. The reversal of 103131120214 is 412021131301.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a super-3 number, since 3×1031311202143 (a number of 34 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 103131120191 and 103131120200.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8483482 + ... + 8495629.

It is an arithmetic number, because the mean of its divisors is an integer number (19343453346).

Almost surely, 2103131120214 is an apocalyptic number.

103131120214 is a deficient number, since it is larger than the sum of its proper divisors (51616506554).

103131120214 is a wasteful number, since it uses less digits than its factorization.

103131120214 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 16982150.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 103131120214 its reverse (412021131301), we get a palindrome (515152251515).

The spelling of 103131120214 in words is "one hundred three billion, one hundred thirty-one million, one hundred twenty thousand, two hundred fourteen".

Divisors: 1 2 3037 6074 16979111 33958222 51565560107 103131120214