103131313333 has 4 divisors (see below), whose sum is σ = 103884096780. Its totient is φ = 102378529888.

The previous prime is 103131313319. The next prime is 103131313343. The reversal of 103131313333 is 333313131301.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 333313131301 = 3461 ⋅96305441.

It can be written as a sum of positive squares in 2 ways, for example, as 82347189444 + 20784123889 = 286962^2 + 144167^2 .

It is a cyclic number.

It is not a de Polignac number, because 103131313333 - 2⁵ = 103131313301 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 103131313298 and 103131313307.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (103131313343) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 376391518 + ... + 376391791.

It is an arithmetic number, because the mean of its divisors is an integer number (25971024195).

Almost surely, 2^103131313333 is an apocalyptic number.

It is an amenable number.

103131313333 is a deficient number, since it is larger than the sum of its proper divisors (752783447).

103131313333 is an equidigital number, since it uses as much as digits as its factorization.

103131313333 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 752783446.

The product of its (nonzero) digits is 2187, while the sum is 25.

Adding to 103131313333 its reverse (333313131301), we get a palindrome (436444444634).

The spelling of 103131313333 in words is "one hundred three billion, one hundred thirty-one million, three hundred thirteen thousand, three hundred thirty-three".