103132100040 has 256 divisors, whose sum is σ = 336040773120. Its totient is φ = 25223577600.

The previous prime is 103132100011. The next prime is 103132100081. The reversal of 103132100040 is 40001231301.

103132100040 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a Harshad number since it is a multiple of its sum of digits (15).

It is a junction number, because it is equal to n+sod(n) for n = 103132099992 and 103132100019.

It is an unprimeable number.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 16322962 + ... + 16329278.

It is an arithmetic number, because the mean of its divisors is an integer number (1312659270).

Almost surely, 2^103132100040 is an apocalyptic number.

103132100040 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 103132100040, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (168020386560).

103132100040 is an abundant number, since it is smaller than the sum of its proper divisors (232908673080).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

103132100040 is a wasteful number, since it uses less digits than its factorization.

103132100040 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6552 (or 6548 counting only the distinct ones).

The product of its (nonzero) digits is 72, while the sum is 15.

Adding to 103132100040 its reverse (40001231301), we get a palindrome (143133331341).

The spelling of 103132100040 in words is "one hundred three billion, one hundred thirty-two million, one hundred thousand, forty".