Base | Representation |
---|---|
bin | 1001011000010011101101… |
… | …1011011000011011110111 |
3 | 1100111221012120201012122011 |
4 | 2112010323123120123313 |
5 | 2322432430124331130 |
6 | 33533454101345051 |
7 | 2113051021304563 |
oct | 226047333303367 |
9 | 40457176635564 |
10 | 10313213511415 |
11 | 331689a186a91 |
12 | 11a692a408187 |
13 | 59a6bb664029 |
14 | 27923b0d86a3 |
15 | 12d40c67b52a |
hex | 9613b6d86f7 |
10313213511415 has 4 divisors (see below), whose sum is σ = 12375856213704. Its totient is φ = 8250570809128.
The previous prime is 10313213511331. The next prime is 10313213511431. The reversal of 10313213511415 is 51411531231301.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 10313213511415 - 29 = 10313213510903 is a prime.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1031321351137 + ... + 1031321351146.
It is an arithmetic number, because the mean of its divisors is an integer number (3093964053426).
Almost surely, 210313213511415 is an apocalyptic number.
10313213511415 is a deficient number, since it is larger than the sum of its proper divisors (2062642702289).
10313213511415 is an equidigital number, since it uses as much as digits as its factorization.
10313213511415 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2062642702288.
The product of its (nonzero) digits is 5400, while the sum is 31.
Adding to 10313213511415 its reverse (51411531231301), we get a palindrome (61724744742716).
The spelling of 10313213511415 in words is "ten trillion, three hundred thirteen billion, two hundred thirteen million, five hundred eleven thousand, four hundred fifteen".
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