Base | Representation |
---|---|
bin | 10011001101011011… |
… | …11011111001011001 |
3 | 222121202012111200122 |
4 | 21212231323321121 |
5 | 132110143034231 |
6 | 4423212443025 |
7 | 513400125242 |
oct | 114655737131 |
9 | 28552174618 |
10 | 10313252441 |
11 | 4412620228 |
12 | 1bb9a79475 |
13 | c8487834b |
14 | 6db9c5cc9 |
15 | 40563877b |
hex | 266b7be59 |
10313252441 has 4 divisors (see below), whose sum is σ = 10532683392. Its totient is φ = 10093821492.
The previous prime is 10313252423. The next prime is 10313252471. The reversal of 10313252441 is 14425231301.
It is a happy number.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-10313252441 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 10313252441.
It is not an unprimeable number, because it can be changed into a prime (10313252471) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 109715405 + ... + 109715498.
It is an arithmetic number, because the mean of its divisors is an integer number (2633170848).
Almost surely, 210313252441 is an apocalyptic number.
It is an amenable number.
10313252441 is a deficient number, since it is larger than the sum of its proper divisors (219430951).
10313252441 is an equidigital number, since it uses as much as digits as its factorization.
10313252441 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 219430950.
The product of its (nonzero) digits is 2880, while the sum is 26.
Adding to 10313252441 its reverse (14425231301), we get a palindrome (24738483742).
The spelling of 10313252441 in words is "ten billion, three hundred thirteen million, two hundred fifty-two thousand, four hundred forty-one".
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