Base | Representation |
---|---|
bin | 10111011100110010000101… |
… | …111101000110110110011011 |
3 | 111112011102022020111112112002 |
4 | 113130302011331012312123 |
5 | 102004212342014200443 |
6 | 1003202351434511215 |
7 | 30503053635454232 |
oct | 2734620575066633 |
9 | 445142266445462 |
10 | 103133002100123 |
11 | 2a952508017266 |
12 | b697a4989550b |
13 | 45715287b8a78 |
14 | 1b67941ba5b19 |
15 | bdcad56d32b8 |
hex | 5dcc85f46d9b |
103133002100123 has 2 divisors, whose sum is σ = 103133002100124. Its totient is φ = 103133002100122.
The previous prime is 103133002100113. The next prime is 103133002100173. The reversal of 103133002100123 is 321001200331301.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 103133002100123 - 220 = 103133001051547 is a prime.
It is a super-2 number, since 2×1031330021001232 (a number of 29 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 103133002100095 and 103133002100104.
It is not a weakly prime, because it can be changed into another prime (103133002100113) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51566501050061 + 51566501050062.
It is an arithmetic number, because the mean of its divisors is an integer number (51566501050062).
Almost surely, 2103133002100123 is an apocalyptic number.
103133002100123 is a deficient number, since it is larger than the sum of its proper divisors (1).
103133002100123 is an equidigital number, since it uses as much as digits as its factorization.
103133002100123 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 324, while the sum is 20.
Adding to 103133002100123 its reverse (321001200331301), we get a palindrome (424134202431424).
The spelling of 103133002100123 in words is "one hundred three trillion, one hundred thirty-three billion, two million, one hundred thousand, one hundred twenty-three".
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