Base | Representation |
---|---|
bin | 11110000001000000011… |
… | …00111100001000110001 |
3 | 10122121001022212222020212 |
4 | 33000200030330020301 |
5 | 113344132044222001 |
6 | 2105442040513505 |
7 | 134340243606551 |
oct | 17004014741061 |
9 | 3577038788225 |
10 | 1031332414001 |
11 | 36842729631a |
12 | 147a6717b895 |
13 | 7633c707596 |
14 | 37cb980d161 |
15 | 1bc623347bb |
hex | f02033c231 |
1031332414001 has 2 divisors, whose sum is σ = 1031332414002. Its totient is φ = 1031332414000.
The previous prime is 1031332413953. The next prime is 1031332414061. The reversal of 1031332414001 is 1004142331301.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1025318256400 + 6014157601 = 1012580^2 + 77551^2 .
It is an emirp because it is prime and its reverse (1004142331301) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1031332414001 - 222 = 1031328219697 is a prime.
It is not a weakly prime, because it can be changed into another prime (1031332414061) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 515666207000 + 515666207001.
It is an arithmetic number, because the mean of its divisors is an integer number (515666207001).
Almost surely, 21031332414001 is an apocalyptic number.
It is an amenable number.
1031332414001 is a deficient number, since it is larger than the sum of its proper divisors (1).
1031332414001 is an equidigital number, since it uses as much as digits as its factorization.
1031332414001 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 864, while the sum is 23.
Adding to 1031332414001 its reverse (1004142331301), we get a palindrome (2035474745302).
The spelling of 1031332414001 in words is "one trillion, thirty-one billion, three hundred thirty-two million, four hundred fourteen thousand, one".
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