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10313330113 = 36307284059
BaseRepresentation
bin10011001101011100…
…01110110111000001
3222121202100110020101
421212232032313001
5132110203030423
64423214242401
7513400600552
oct114656166701
928552313211
1010313330113
114412673619
121bb9ab6401
13c848a47c8
146dba06329
154056517ad
hex266b8edc1

10313330113 has 4 divisors (see below), whose sum is σ = 10313650480. Its totient is φ = 10313009748.

The previous prime is 10313330089. The next prime is 10313330119. The reversal of 10313330113 is 31103331301.

It is a happy number.

10313330113 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 10313330113 - 25 = 10313330081 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (10313330119) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 105723 + ... + 178336.

It is an arithmetic number, because the mean of its divisors is an integer number (2578412620).

Almost surely, 210313330113 is an apocalyptic number.

It is an amenable number.

10313330113 is a deficient number, since it is larger than the sum of its proper divisors (320367).

10313330113 is an equidigital number, since it uses as much as digits as its factorization.

10313330113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 320366.

The product of its (nonzero) digits is 243, while the sum is 19.

Adding to 10313330113 its reverse (31103331301), we get a palindrome (41416661414).

The spelling of 10313330113 in words is "ten billion, three hundred thirteen million, three hundred thirty thousand, one hundred thirteen".

Divisors: 1 36307 284059 10313330113