Base | Representation |
---|---|
bin | 10011001101011100… |
… | …01110110111000111 |
3 | 222121202100110020121 |
4 | 21212232032313013 |
5 | 132110203030434 |
6 | 4423214242411 |
7 | 513400600561 |
oct | 114656166707 |
9 | 28552313217 |
10 | 10313330119 |
11 | 4412673624 |
12 | 1bb9ab6407 |
13 | c848a4801 |
14 | 6dba06331 |
15 | 4056517b4 |
hex | 266b8edc7 |
10313330119 has 2 divisors, whose sum is σ = 10313330120. Its totient is φ = 10313330118.
The previous prime is 10313330089. The next prime is 10313330149. The reversal of 10313330119 is 91103331301.
It is a balanced prime because it is at equal distance from previous prime (10313330089) and next prime (10313330149).
It is a cyclic number.
It is not a de Polignac number, because 10313330119 - 217 = 10313199047 is a prime.
It is a super-2 number, since 2×103133301192 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 10313330093 and 10313330102.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (10313330149) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5156665059 + 5156665060.
It is an arithmetic number, because the mean of its divisors is an integer number (5156665060).
Almost surely, 210313330119 is an apocalyptic number.
10313330119 is a deficient number, since it is larger than the sum of its proper divisors (1).
10313330119 is an equidigital number, since it uses as much as digits as its factorization.
10313330119 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 729, while the sum is 25.
The spelling of 10313330119 in words is "ten billion, three hundred thirteen million, three hundred thirty thousand, one hundred nineteen".
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