103134113 has 2 divisors, whose sum is σ = 103134114. Its totient is φ = 103134112.

The previous prime is 103134107. The next prime is 103134137. The reversal of 103134113 is 311431301.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 78996544 + 24137569 = 8888^2 + 4913^2 .

It is a cyclic number.

It is not a de Polignac number, because 103134113 - 2¹⁰ = 103133089 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 103134091 and 103134100.

It is not a weakly prime, because it can be changed into another prime (103134193) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51567056 + 51567057.

It is an arithmetic number, because the mean of its divisors is an integer number (51567057).

Almost surely, 2^103134113 is an apocalyptic number.

It is an amenable number.

103134113 is a deficient number, since it is larger than the sum of its proper divisors (1).

103134113 is an equidigital number, since it uses as much as digits as its factorization.

103134113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 108, while the sum is 17.

The square root of 103134113 is about 10155.4966889857. The cubic root of 103134113 is about 468.9581767358.

Adding to 103134113 its reverse (311431301), we get a palindrome (414565414).

The spelling of 103134113 in words is "one hundred three million, one hundred thirty-four thousand, one hundred thirteen".