1031401411 has 2 divisors, whose sum is σ = 1031401412. Its totient is φ = 1031401410.

The previous prime is 1031401391. The next prime is 1031401421. The reversal of 1031401411 is 1141041301.

It is a strong prime.

It is an emirp because it is prime and its reverse (1141041301) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1031401411 - 2⁹ = 1031400899 is a prime.

It is a super-2 number, since 2×1031401411² = 2127577741225581842, which contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1031401421) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 515700705 + 515700706.

It is an arithmetic number, because the mean of its divisors is an integer number (515700706).

Almost surely, 2^1031401411 is an apocalyptic number.

1031401411 is a deficient number, since it is larger than the sum of its proper divisors (1).

1031401411 is an equidigital number, since it uses as much as digits as its factorization.

1031401411 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 48, while the sum is 16.

The square root of 1031401411 is about 32115.4388262094. The cubic root of 1031401411 is about 1010.3594482464.

Adding to 1031401411 its reverse (1141041301), we get a palindrome (2172442712).

The spelling of 1031401411 in words is "one billion, thirty-one million, four hundred one thousand, four hundred eleven".