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1031411012537 is a prime number
BaseRepresentation
bin11110000001001001110…
…00110001001110111001
310122121020210210012011202
433000210320301032321
5113344312204400122
62105453525303545
7134342216645033
oct17004470611671
93577223705152
101031411012537
1136846769a594
12147a89564bb5
1376352a96aa9
1437cc602cc53
151bc691ace92
hexf024e313b9

1031411012537 has 2 divisors, whose sum is σ = 1031411012538. Its totient is φ = 1031411012536.

The previous prime is 1031411012503. The next prime is 1031411012551. The reversal of 1031411012537 is 7352101141301.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 951036494521 + 80374518016 = 975211^2 + 283504^2 .

It is a cyclic number.

It is not a de Polignac number, because 1031411012537 - 218 = 1031410750393 is a prime.

It is not a weakly prime, because it can be changed into another prime (1031411011537) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 515705506268 + 515705506269.

It is an arithmetic number, because the mean of its divisors is an integer number (515705506269).

Almost surely, 21031411012537 is an apocalyptic number.

It is an amenable number.

1031411012537 is a deficient number, since it is larger than the sum of its proper divisors (1).

1031411012537 is an equidigital number, since it uses as much as digits as its factorization.

1031411012537 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2520, while the sum is 29.

Adding to 1031411012537 its reverse (7352101141301), we get a palindrome (8383512153838).

The spelling of 1031411012537 in words is "one trillion, thirty-one billion, four hundred eleven million, twelve thousand, five hundred thirty-seven".