Base | Representation |
---|---|
bin | 11110000001001010000… |
… | …01100010101010000001 |
3 | 10122121020222010000121211 |
4 | 33000211001202222001 |
5 | 113344313301442004 |
6 | 2105454050450121 |
7 | 134342245333264 |
oct | 17004501425201 |
9 | 3577228100554 |
10 | 1031413312129 |
11 | 368468a20282 |
12 | 147a8a293941 |
13 | 763533c06b5 |
14 | 37cc646acdb |
15 | 1bc694b4504 |
hex | f025062a81 |
1031413312129 has 2 divisors, whose sum is σ = 1031413312130. Its totient is φ = 1031413312128.
The previous prime is 1031413312121. The next prime is 1031413312157. The reversal of 1031413312129 is 9212133141301.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1031412892225 + 419904 = 1015585^2 + 648^2 .
It is a cyclic number.
It is not a de Polignac number, because 1031413312129 - 23 = 1031413312121 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 1031413312129.
It is not a weakly prime, because it can be changed into another prime (1031413312121) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 515706656064 + 515706656065.
It is an arithmetic number, because the mean of its divisors is an integer number (515706656065).
Almost surely, 21031413312129 is an apocalyptic number.
It is an amenable number.
1031413312129 is a deficient number, since it is larger than the sum of its proper divisors (1).
1031413312129 is an equidigital number, since it uses as much as digits as its factorization.
1031413312129 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3888, while the sum is 31.
The spelling of 1031413312129 in words is "one trillion, thirty-one billion, four hundred thirteen million, three hundred twelve thousand, one hundred twenty-nine".
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