Base | Representation |
---|---|
bin | 10111011100111010100100… |
… | …010011100100110111010101 |
3 | 111112012021210101010210122220 |
4 | 113130322210103210313111 |
5 | 102004340010404210201 |
6 | 1003210454401012553 |
7 | 30503525264052513 |
oct | 2734724423446725 |
9 | 445167711123586 |
10 | 103142101241301 |
11 | 2a956357272751 |
12 | b699769024159 |
13 | 457234896b985 |
14 | 1b681664274b3 |
15 | bdce69445036 |
hex | 5dcea44e4dd5 |
103142101241301 has 128 divisors (see below), whose sum is σ = 153912045404160. Its totient is φ = 61160516812800.
The previous prime is 103142101241219. The next prime is 103142101241323.
103142101241301 is nontrivially palindromic in base 10.
It is not a de Polignac number, because 103142101241301 - 223 = 103142092852693 is a prime.
It is a super-3 number, since 3×1031421012413013 (a number of 43 digits) contains 333 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (103142101241341) by changing a digit.
It is a polite number, since it can be written in 127 ways as a sum of consecutive naturals, for example, 49996170196 + ... + 49996172258.
It is an arithmetic number, because the mean of its divisors is an integer number (1202437854720).
Almost surely, 2103142101241301 is an apocalyptic number.
It is an amenable number.
103142101241301 is a deficient number, since it is larger than the sum of its proper divisors (50769944162859).
103142101241301 is a wasteful number, since it uses less digits than its factorization.
103142101241301 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3987.
The product of its (nonzero) digits is 576, while the sum is 24.
It can be divided in two parts, 10314210 and 1241301, that added together give a palindrome (11555511).
The spelling of 103142101241301 in words is "one hundred three trillion, one hundred forty-two billion, one hundred one million, two hundred forty-one thousand, three hundred one".
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