10314211130 has 8 divisors (see below), whose sum is σ = 18565580052. Its totient is φ = 4125684448.

The previous prime is 10314211129. The next prime is 10314211163. The reversal of 10314211130 is 3111241301.

It can be written as a sum of positive squares in 2 ways, for example, as 10227479161 + 86731969 = 101131^2 + 9313^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 10314211099 and 10314211108.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 515710547 + ... + 515710566.

Almost surely, 2^10314211130 is an apocalyptic number.

10314211130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

10314211130 is a deficient number, since it is larger than the sum of its proper divisors (8251368922).

10314211130 is a wasteful number, since it uses less digits than its factorization.

10314211130 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1031421120.

The product of its (nonzero) digits is 72, while the sum is 17.

Adding to 10314211130 its reverse (3111241301), we get a palindrome (13425452431).

The spelling of 10314211130 in words is "ten billion, three hundred fourteen million, two hundred eleven thousand, one hundred thirty".