10314341113 has 2 divisors, whose sum is σ = 10314341114. Its totient is φ = 10314341112.

The previous prime is 10314341069. The next prime is 10314341117. The reversal of 10314341113 is 31114341301.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 8508771049 + 1805570064 = 92243^2 + 42492^2 .

It is an emirp because it is prime and its reverse (31114341301) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 10314341113 - 2¹³ = 10314332921 is a prime.

It is not a weakly prime, because it can be changed into another prime (10314341117) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5157170556 + 5157170557.

It is an arithmetic number, because the mean of its divisors is an integer number (5157170557).

Almost surely, 2^10314341113 is an apocalyptic number.

It is an amenable number.

10314341113 is a deficient number, since it is larger than the sum of its proper divisors (1).

10314341113 is an equidigital number, since it uses as much as digits as its factorization.

10314341113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 432, while the sum is 22.

Adding to 10314341113 its reverse (31114341301), we get a palindrome (41428682414).

The spelling of 10314341113 in words is "ten billion, three hundred fourteen million, three hundred forty-one thousand, one hundred thirteen".