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103144512113 is a prime number
BaseRepresentation
bin110000000001111100…
…1000101101001110001
3100212020022121002221022
41200003321011221301
53142214443341423
6115214532505225
710311005613206
oct1400371055161
9325208532838
10103144512113
113a81a42a645
1217ba6a7b215
13995a120cb6
144dc6923cad
152a3a326dc8
hex1803e45a71

103144512113 has 2 divisors, whose sum is σ = 103144512114. Its totient is φ = 103144512112.

The previous prime is 103144512091. The next prime is 103144512143. The reversal of 103144512113 is 311215441301.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 71456239969 + 31688272144 = 267313^2 + 178012^2 .

It is a cyclic number.

It is not a de Polignac number, because 103144512113 - 210 = 103144511089 is a prime.

It is not a weakly prime, because it can be changed into another prime (103144512143) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51572256056 + 51572256057.

It is an arithmetic number, because the mean of its divisors is an integer number (51572256057).

Almost surely, 2103144512113 is an apocalyptic number.

It is an amenable number.

103144512113 is a deficient number, since it is larger than the sum of its proper divisors (1).

103144512113 is an equidigital number, since it uses as much as digits as its factorization.

103144512113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1440, while the sum is 26.

Adding to 103144512113 its reverse (311215441301), we get a palindrome (414359953414).

The spelling of 103144512113 in words is "one hundred three billion, one hundred forty-four million, five hundred twelve thousand, one hundred thirteen".