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10315455012361 is a prime number
BaseRepresentation
bin1001011000011100000100…
…0010000001111000001001
31100112010222210111020212201
42112013001002001320021
52323002022440343421
633534504332440201
72113160406613012
oct226070102017011
940463883436781
1010315455012361
11331783a481904
1211a7255019061
1359a987b66455
142793b0a9a009
1512d4de344b91
hex961c1081e09

10315455012361 has 2 divisors, whose sum is σ = 10315455012362. Its totient is φ = 10315455012360.

The previous prime is 10315455012353. The next prime is 10315455012469. The reversal of 10315455012361 is 16321055451301.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 9102771726400 + 1212683285961 = 3017080^2 + 1101219^2 .

It is a cyclic number.

It is not a de Polignac number, because 10315455012361 - 23 = 10315455012353 is a prime.

It is a super-2 number, since 2×103154550123612 (a number of 27 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 10315455012361.

It is not a weakly prime, because it can be changed into another prime (10315455012061) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5157727506180 + 5157727506181.

It is an arithmetic number, because the mean of its divisors is an integer number (5157727506181).

Almost surely, 210315455012361 is an apocalyptic number.

It is an amenable number.

10315455012361 is a deficient number, since it is larger than the sum of its proper divisors (1).

10315455012361 is an equidigital number, since it uses as much as digits as its factorization.

10315455012361 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 54000, while the sum is 37.

The spelling of 10315455012361 in words is "ten trillion, three hundred fifteen billion, four hundred fifty-five million, twelve thousand, three hundred sixty-one".