Base | Representation |
---|---|
bin | 11110000001100111101… |
… | …00000010100101011011 |
3 | 10122121220020222202220111 |
4 | 33000303310002211123 |
5 | 113400320311244011 |
6 | 2105534432505151 |
7 | 134351350322302 |
oct | 17006364024533 |
9 | 3577806882814 |
10 | 1031661431131 |
11 | 368585a89801 |
12 | 147b393ab1b7 |
13 | 76392924b86 |
14 | 37d0b3b7439 |
15 | 1bc81176121 |
hex | f033d0295b |
1031661431131 has 2 divisors, whose sum is σ = 1031661431132. Its totient is φ = 1031661431130.
The previous prime is 1031661431057. The next prime is 1031661431183. The reversal of 1031661431131 is 1311341661301.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1031661431131 - 211 = 1031661429083 is a prime.
It is a super-2 number, since 2×10316614311312 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1031661431093 and 1031661431102.
It is not a weakly prime, because it can be changed into another prime (1031661431191) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 515830715565 + 515830715566.
It is an arithmetic number, because the mean of its divisors is an integer number (515830715566).
Almost surely, 21031661431131 is an apocalyptic number.
1031661431131 is a deficient number, since it is larger than the sum of its proper divisors (1).
1031661431131 is an equidigital number, since it uses as much as digits as its factorization.
1031661431131 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3888, while the sum is 31.
The spelling of 1031661431131 in words is "one trillion, thirty-one billion, six hundred sixty-one million, four hundred thirty-one thousand, one hundred thirty-one".
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