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103200022013 = 119381820183
BaseRepresentation
bin110000000011100110…
…0110101110111111101
3100212101012001022012112
41200013030311313331
53142323201201023
6115224234343405
710312251466514
oct1400714656775
9325335038175
10103200022013
113a8487a3aa0
121800158ab65
1399687882aa
144dd005367b
152a4013e478
hex1807335dfd

103200022013 has 4 divisors (see below), whose sum is σ = 112581842208. Its totient is φ = 93818201820.

The previous prime is 103200021989. The next prime is 103200022043. The reversal of 103200022013 is 310220002301.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 103200022013 - 212 = 103200017917 is a prime.

It is a Curzon number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (103200022043) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4690910081 + ... + 4690910102.

It is an arithmetic number, because the mean of its divisors is an integer number (28145460552).

Almost surely, 2103200022013 is an apocalyptic number.

It is an amenable number.

103200022013 is a deficient number, since it is larger than the sum of its proper divisors (9381820195).

103200022013 is an equidigital number, since it uses as much as digits as its factorization.

103200022013 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 9381820194.

The product of its (nonzero) digits is 72, while the sum is 14.

Adding to 103200022013 its reverse (310220002301), we get a palindrome (413420024314).

The spelling of 103200022013 in words is "one hundred three billion, two hundred million, twenty-two thousand, thirteen".

Divisors: 1 11 9381820183 103200022013